Pointer of a character in C++

Question

Going by the books, the first cout line should print me the address of the location where the char variable b is stored, which seems to be the case for the

Answer 1

Actually this program has problem. There is a memory leak.

char *c=new char[10];
c=&b;

This allocates 10 characters on heap, but then the pointer to heap is overwritten with the address of the variable b.

When a char* is written to cout with operator<< then it is considered as a null terminated C-string. As the address of b was initialized to a single character containing d op<< continues to search on the stack finding the first null character. It seems the it was found after a few characters, so dh^# is written (the d is the value of variable b the rest is just some random characters found on the stack before the 1st \0 char).

If you want to get the address try to use static_cast(c).

My example:

int main() {
  char *c;
  char b = 'd';
  c = &b; 
  cout << c << ", " << static_cast(c) << endl;
}

An the output:

dÌÿÿ, 0xffffcc07

See the strange characters after 'd'.

I hope this could help a bit!