C: problem with char*

Question

/*
 * code.c
 *
 * TASK
 *      Reverse a string by reversing pointers. Function should use return
 *      type char* and use a char* parameter as input.
 */
#include &l         


        

Answer 1

This works if I set the return type to void:

/*
 * code.c
 *
 * TASK
 *      Reverse a string by reversing pointers. Function should use return
 *      type char* and use a char* parameter as input.
 */
#include 
#include 
#define STRMAX 51

void reverse(char* sPhrase[]);

int main() {
    char sPhrase[STRMAX];
    char* sPPhrase[STRMAX];
    char* sPReverse[STRMAX];
    int iCntr;

    printf("Enter string (max. 50 chars): ");
    gets(sPhrase);

    for (iCntr = 0; iCntr < strlen(sPhrase); iCntr++) {
        sPPhrase[iCntr] = &sPhrase[iCntr];
    }

    reverse(sPPhrase);          // Disabled return type char*

    return 0;
}

void reverse(char* sPPhrase[]) {
    char* sPOutput[STRMAX];
    int iCnt = 0, iCntRev;

    for (iCntRev = strlen(*sPPhrase)-2; iCntRev >= 0; iCntRev--) {
        sPOutput[iCnt] = sPPhrase[iCntRev];
        iCnt++;
    }

    *sPOutput[iCnt] = '\0';      // Don't forget to close the string

    // return sPOutput;     // Disabled return type char*
}

As soon as I get the return types back into play, things go wrong. sPReverse = reverse(sPPhrase); still returns the incompatible types in assignment error even though the return type is the same as the type of the variable I'm storing the returned pointer array in.