Max HEX value for long type

Question

I have ported Java code to C#. Could you please explain why I have compile-time error in the follow line (I use VS 2008):

    private long l = 0xffffffffffffffff         


        

Answer 1

Java doesn't mind if a constant overflows in this particular situation - the value you've given is actually -1.

The simplest way of achieving the same effect in C# is:

private long l = -1;

If you want to retain the 16 fs you could use:

private long l = unchecked((long) 0xffffffffffffffffUL);

If you actually want the maximum value for a signed long, you should use:

// Java
private long l = Long.MAX_VALUE;
// C#
private long l = long.MaxValue;