The aim is to show a form which will update the div on the page with the result
In the example that doesn't work, if you bind the ajaxForm when you display the form it should work fine.
// you may want to use better/faster selector then 'a' but in this example it
// will work
$('a').click(function () {
$('#feditform').fadeIn('slow').ajaxForm(options);
return false;
});
Add above instead of jQuery.facybox({ div: '#formDiv' }); return false and it should work as expected.