JS: Filter array only for non-empty and type of string values

Question

I am trying to filter an array like this:

array.filter(e => { return e })

With this I want to filter all empty strings including undef

Answer 1

You can check the type of the elements using typeof:

array.filter(e => typeof e === 'string' && e !== '')

Since '' is falsy, you could simplify by just testing if e was truthy, though the above is more explicit

array.filter(e => typeof e === 'string' && e)

const array = [null, undefined, '', 'hello', '', 'world', 7, ['some', 'array'], null]

console.log(
  array.filter(e => typeof e === 'string' && e !== '')
)