GetType() and Typeof() in C#

Question

itemVal = \"0\";

res = int.TryParse(itemVal, out num);

if ((res == true) && (num.GetType() == typeof(byte)))  
    return true;
else
   return false;  // goes          


        

Answer 1

Because num is an int, not a byte.

GetType() gets the System.Type of the object at runtime. In this case, it's the same as typeof(int), since num is an int.

typeof() gets the System.Type object of a type at compile-time.

Your comment indicates you're trying to determine if the number fits into a byte or not; the contents of the variable do not affect its type (actually, it's the type of the variable that restricts what its contents can be).

You can check if the number would fit into a byte this way:

if ((num >= 0) && (num < 256)) {
    // ...
}

Or this way, using a cast:

if (unchecked((byte)num) == num) {
    // ...
}

It seems your entire code sample could be replaced by the following, however:

byte num;
return byte.TryParse(itemVal, num);