memory corruption

Question

i was running a small c program:

#include
int main()
{
char *p;
p = (char *)malloc(10);
free(p);
free(p);
free(p);
printf(\"\\npointer is freed!!\         


        

Answer 1

As per the man page, "if free(ptr) has already been called before, undefined behavior occurs."

It doesn't need to blow up; "not doing anything" is perfectly acceptable undefined behaviour. Also are nasal demons. Don't rely on it.