SFINAE did not compile [duplicate]

Answer 1

Another syntax which compiles and works is to move the enable_is as the return type:

class X
{
public:
    template 
    typename std::enable_if< std::is_floating_point::value, void>::type Do()
    {
        std::cout << "yes" << std::endl;
    }

    template 
    typename std::enable_if< !std::is_floating_point::value, void>::type Do()
    {
        std::cout << "no" << std::endl;
    }

};

int main()
{
    X x;
    x.Do();
    getchar();
}