Printing out characters in an X pattern using for loops

Question

I\'m trying to print this big X pattern:

 x       x
  x     x
   x   x
    x x
     x
    x x
   x   x
  x     x
 x       x

I can\'t figure out

Answer 1

Here's your program with minimum modifications to do what you want:

#include 
int main()
{
  int j,i;
  char ch[] = "x";               // (1)
  int sz = 8;                    // (2)
  for( j = sz; j >= 0 ; --j)
    {
      for(i = sz; i>=0; --i)
        {
          if(sz-j == i || i == j)// (3) 
          {
             printf("%s",ch);
          } else {
             printf(" ");        // (4)
          }
        }
      printf("\n");
    }
  return 0;
}

Explanation:

(1) First of all, if you want x, you should print x :)

(2) Use a variable for the size, so you can play with it ...

(3) You have to print two x per line, i.e. in two positions in the inner loop.

These positions lie on the two diagonals where either x == y (here i == j), or x == 8 - y (here i == sz -j)

(4) You have to print a space otherwise

See here: https://eval.in/228155