Printing out characters in an X pattern using for loops

Question

I\'m trying to print this big X pattern:

 x       x
  x     x
   x   x
    x x
     x
    x x
   x   x
  x     x
 x       x

I can\'t figure out

Answer 1

A slight extension to one of the good solutions above for the cross ended up being a bit more than just crossing x's:

#include 

int main(){
    int n = 4 - 1;
    char ch[] = "x";
    int i = 0, dx = 1;

    printf ("\n  __\n  ||----------------------------\n");
    do {
        printf ("  %s %*s%*.*s %*c\n", "||", 4*i+1, ch, 8*(n-i), 8*(n-i), ch, 4*i+1, '|');
        if ((i += dx)==n)
            dx = -dx;
    } while (i>=0);
    printf ("  ||----------------------------\n");
    for (i = 0; i < 10; i++)
        printf ("  ||\n");
    printf ("------\n\n");

    return 0;
}

output:

$ ./bin/flag

  __
  ||----------------------------
  || x                       x |
  ||     x               x     |
  ||         x       x         |
  ||             x             |
  ||         x       x         |
  ||     x               x     |
  || x                       x |
  ||----------------------------
  ||
  ||
  ||
  ||
  ||
  ||
  ||
  ||
  ||
  ||
------