Why Segmentation fault in following code?

Question

I read this on wikipedia

    int main(void)
 {

    char *s = \"hello world\";
    *s = \'H\';

 }

When the program containing this code is com

Answer 1

String literals are stored in read-only memory, that's just how it works. Your code uses a pointer initialized to point at the memory where a string literal is stored, and thus you can't validly modify that memory.

To get a string in modifiable memory, do this:

char s[] = "hello world";

then you're fine, since now you're just using the constant string to initialize a non-constant array.