Dataframe list comprehension “zip(…)”: loop through chosen df columns efficiently with just a list of column name strings

Question

This is just a nitpicking syntactic question...

I have a dataframe, and I want to use list comprehension to evaluate a function using lots of columns.

I know I c

Answer 1

As mentioned in the comments above, you should use apply instead:

df['reult_col'] = df.apply(lambda x: some_func(*tuple(x.values)), axis=1)