PHP: How to check if a number has more than two decimals

Question

I\'m trying to pick out numbers with more than two decimals (more than two digits after the decimal separator). I cant\'t figure out why this doesn\'t work:

if (         


        

Answer 1

You could use the following function (works with negative numbers, too):

function decimalCheck($num) {
    $decimals = ( (int) $num != $num ) ? (strlen($num) - strpos($num, '.')) - 1 : 0;
    return $decimals >= 2;
}

Test cases:

$numbers = array(
    32.45,
    32.44,
    123.21,
    21.5454,
    1.545400,
    2.201054,
    0.05445,
    32,
    12.0545400,
    12.64564,
    -454.44,
    -0.5454
);
foreach ($numbers as $number) {
    echo $number. "\t : \t";
    echo (decimalCheck($number)) ? 'true' : 'false';
    echo "
";
}

Output:

32.45    :  true
32.44    :  true
123.21   :  true
21.5454  :  true
1.5454   :  true
2.201054 :  true
0.05445  :  true
32       :  false
12.05454 :  true
12.64564 :  true
-454.44  :  true
-0.5454  :  true

Demo.