Allocating memory using new returns same memory address

Question

class abc  {
    int x ;
};
int main()
{
    abc *A = new abc ;
    cout<< static_cast(A) << endl ;
    delete A ;
    cout<< static_cast&         


        

Answer 1

abc *A = new abc ;
cout<< static_cast(A) << endl ;

This is the first output.

delete A ;
cout<< static_cast(A) << endl ;

Though it is after delete the value of A remains the same. What delete did was: 1. call the destructor (in this case trivial) of A and 2. Inform the memory allocator that the memory allocated for A is now free and can be used for other purposes.

abc *B = new abc ;
cout<< static_cast(B) << endl ;

It may be that in this step output will be still the same - since allocator has the memory previously allocated for A for use now, it may use it for B.

delete B ;
cout<< static_cast(B) << endl ;

The same as before with A.