Python miminum value in dictionary of lists

Question

Sorry about the question repost...I should have just edited this question in the first place. Flagged the new one for the mods. Sorry for the trouble

Had to re-write the

Answer 1

You can use min() with a key= argument, and specify a key function that compares the way you want.

d = {'a': ['1'], 'b': ['1', '2'], 'c': ['2'], 'd':['1']}

min_value = min(d.values())
min_list = [key for key, value in d.items() if value == min_value]
max_len = len(max(d.values(), key=len))
long_list = [key for key, value in d.items() if len(value) == max_len]

print(min_list)
print(long_list)

Notes:

0) Don't use dict as a variable name; that's the name of the class for dictionary, and if you use it as a variable name you "shadow" it. I just used d for the name here.

1) min_value was easy; no need to use a key= function.

2) max_len uses a key= function, len(), to find the longest value.