Why is it allowed to overwrite a const variable using a pointer to it using memcpy?

Question

Why is it allowed to change a const variable using a pointer to it with memcpy?

This code:

const int i=5;
int j = 0;
memcpy(&j, &i, sizeof(int));         


        

Answer 1

While 'officially' it's undefined in reality it's very much defined - you will change the value of the const variable. Which raises the question why it's const to begin with.