If ([] == false) is true, why does ([] || true) result in []?

Question

Was just doing some testing and I find this odd:

[] == false

Gives true, this makes sense because double equal only compares contents and not t

Answer 1

from the ECMA-262 5.1 (page 83):

If ToBoolean(lval) is true, return lval

[] || false; // []