Deduce template argument for size of initializer list

Question

I have the following (not compilable) code:

template< size_t N >
void foo( std::array )
{
  // Code, where \"N\" is used.
}

int main()
{
  f         


        

Answer 1

Thanks to core issue 1591, you can use

template 
void foo( int const (&arr)[N] )
{
  // Code, where "N" is used.
}

foo({1, 2, 3});