Passing a char pointer array to a function

Question

I have written following sample code to demonstrate my problem

#include 
#include 

using namespace std;

void f (char*** a)
{
           


        

Answer 1

a[0], a[1] are char, and they have a value in them, dereferencing that value will obviously cause a segmentation fault. What you may want to do is:

(*a)[...]

dereference 'a' which is a pointer, this will give u an array.