In PHP, after assigning a file pointer resource to a variable with fopen(), how can I get the file name from the variable?

Question

For example:

$file = fopen(\"File.txt\", \"r\");
$filename = $file->basename;

if there was a method like basename for file objects (file poi

Answer 1

I came to this page while trying to find out the filename that PHP's tmpfile() function had created - it returns a pointer. I wanted to use it to create a file I could use with some Unix commands. In the end I used tempnam(realpath(sys_get_temp_dir()), "piclib_"); instead.