How to print the same char n times in Haskell

Question

I would like to print a char underlining a String n times, with n the length of the String in Haskell.

How should I do this?

My String is: \"Available Chars (x)\

Answer 1

A possibility is to (re)implement replicate, for instance as follows,

replicate' :: Int -> a -> [a]                
replicate' n x = if (n <= 0) then [] else (x : replicate (n-1) x)