Why are array assignments incompatible, even though their data types are?

Question

byte b =10;   
int a = b;   // Primitive data type widening
             // Works perfectly fine

the above code will give no error/warnings. But wh

Answer 1

The array created by new byte[10] can contain 10 byte values. If you were able to assign it to a variable of type int[], the compiler would assume (mistakenly) that your array of bytes can contain 10 int values.

Consider the following code, which is invalid:

byte[] b = new byte[10];
b[0] = 10000; // too large for byte

and the following code, which is valid:

int[] i2 = new int[10];
i2[0] = 10000;

If int[] i2 = new byte[10]; was valid, the compiler would have allowed you to store an int in a variable of type byte.