if command in python

Question

if \"aa\" or \"bb\" or \"cc\" or \"dd\" or \"ee\" or \"ff\" in attrs[\"show\"]:
    self.xx = xxxx

I have a code like this, to check if attrs[\"sho

Answer 1

Try the following:

if any(s in attrs["show"] for s in ("aa", "bb", "cc", "dd", "ee", "ff")):
    self.xx = xxxx

Your current if statement will always evaluate to True, because instead of checking if each string is in attrs["show"] you are checking if "aa" is True, or if "bb" is True, and on and on. Since "aa" will always evaluate as True in a Boolean context, you will always enter the if clause.

Instead, use the any() function as in my example, which accepts an iterable and returns True if any of its elements are True. Similar to a bunch of or's as in your code, this will short-circuit as soon as it finds an element that is True. In this example, the above code is equivalent to the following (but much more concise!):

if ("aa" in attrs["show"] or "bb" in attrs["show"] or "cc" in attrs["show"] or
    "dd" in attrs["show"] or "ee" in attrs["show"] or "ff" in attrs["show"]):
    self.xx = xxxx