The address of character type variable

Question

Here is just a test prototype :

#include 
#include 
using namespace std;

int main()
{
   int a=10;
   char b=\'H\';
   string          


        

Answer 1

There is an overload for << which takes a pointer to char and interprets it as a terminated C-style string. Using this for the address of any other char will go horribly wrong.

Instead, convert to a typeless pointer so that << doesn't get too clever:

cout << static_cast(&b)