How to read the template partial specialization?

Question

Suppose the following declaration:

template  struct MyTemplate;

The following definition of the partial specialization se

Answer 1

There is no contradiction. T should be read as T, T* is T*.

template struct MyTemplate {};

"In the first part of this line (i.e. template ), T is int *."

No - in template T is int, in struct MyTemplate {}; T is also int.

"Note that when a partial specialization is used, a template parameter is deduced from the specialization pattern; the template parameter is not simply the actual template argument. In particular, for Vector, T is Shape and not Shape*." (Stroustrup C++, 4th ed, 25.3, p. 732.)