How to read the template partial specialization?

Question

Suppose the following declaration:

template  struct MyTemplate;

The following definition of the partial specialization se

Answer 1

You have this line:

MyTemplate c;

Your confusion seems to come from assuming that the int * in < > somehow corresponds to the T in template . It does not. In a partial specialisation (actually in every template declaration), the template parameter names are simply "free variable" (or perhaps "placeholder") names. The template arguments (int * in your case) don't directly correspond to these, they correspond to what is (or would be) in the < > following the template name.

This means that the part of the instantiation maps to the part of the partial specialisation. T is just a name introduced by the template prefix. In the entire process, the T is int.