SED: addressing two lines before match

Question

Print line, which is situated 2 lines before the match(pattern).

I tried next:

sed -n \': loop
/.*/h
:x
{n;n;/cen/p;}
s/./c/p
t x
s/n/c/p
t loop
{g;p         


        

Answer 1

This one with grep, a bit simpler solution and easy to read [However need to use one pipe]: grep -B2 'pattern' file_name | sed -n '1,2p'