Search through a 2-dimensional list without numpy

Question

I\'m looking to define a function that accepts two parameters: an int and a list.

If the function finds the integer in the list it returns

Answer 1

Here is my approach:

def matrix_search(target, matrix):
    for row_index, row in enumerate(matrix):
        try:
            return (row_index, row.index(target))
        except ValueError:
            pass
    raise ValueError('Target {} not found'.format(target))

Sample usage:

print(matrix_search(4, l))

Notes

• To search a simple list, use the .index() method
• The .index() method will either return the index of the element if found or throw a ValueError if not found. In our context, we just ignore this exception and move on to the next row.
• At the end of the loop, we will throw an exception because the element is not found