Sum of all rows of all columns - Bash

Question

I have a file like this

1 4 7 ...
2 5 8
3 6 9 

And I would like to have as output

6 15 24 ...

That is the

Answer 1

echo "1 4 7
2 5 8
3 6 9 " \
| awk '{for (i=1;i<=NF;i++){
   sums[i]+=$i;maxi=i}
 }
 END{
   for(i=1;i<=maxi;i++){
     printf("%s ", sums[i])
   }
 print}'

output

6 15 24

My recollection is that you can't rely on for (i in sums) to produce the keys any particular order, but maybe this is "fixed" in newer versions of gawk.

In case you're using an old-line Unix awk, this solution will keep your output in the same column order, regardless of how "wide" your file is.

IHTH