What is static about a base constructor call? [duplicate]

Answer 1

At the point that base(foo = 0) executes the DerivedType class has not been "Created" yet so it can not access the members it defines yet.

The order things happen is like this

1. The user calls new DerivedType()
2. The code calls DerivedType's base(foo = 0)
3. The code calls BaseType's implicit base() to Object()
4. The memory for any fields in Object is allocated and then the Object() constructor is run to completion.
5. The memory for any fields in BaseType is allocated and then the BaseType(int bar) constructor is run to completion.
6. The memory for any fields in DerivedType is allocated and then the DerivedType() constructor is run to completion.

So you see you are attempting to assign a value to foo at step 2, but foo won't exist till step 6.