Regular expression for matching non-whitespace in Python

Question

I want to use re.search to extract the first set of non-whitespace characters. I have the following pseudoscript that recreates my problem:

#!/usr/b         


        

Answer 1

Replace your re.search as below, \S finds non-whitespace character, and + searches for one or more times. Python starts to search from first character.

import re
line = "STARC-1.1.1.5             ConsCase    WARNING    Warning"
m = re.search('\S+',line)
print(m.group(0))