C++ passing method pointer as template argument

Question

I have a caller function like this:

template
void CallMethod(T *object){
    (object->*method)(args);
}
         


        

Answer 1

All template parameters must be known at compile time. So if method is really a variable and not a particular function, there is no way to do what you want.

Instead, you may be able to make a template struct which has a pointer to member function as a member and implements an operator() which acts similarly to CallMethod.