Defaulted constructor vs implicit constructor

Question

It\'s possible that someone has already asked about this but googling for \"default\", \"defaulted\", \"explicit\" and so on doesn\'t give good results. But anyway.

Answer 1

Given below excerpt from C++ Programming Language Stroustrup 4th Edition book makes it clear that they are equivalent.

---

Explicit Defaults

Since the generation of otherwise default operations can be suppressed, there has to be a way of getting back a default. Also, some people prefer to see a complete list of operations in the program text even if that complete list is not needed. For example, we can write:

class gslice {
    valarray size;
    valarray stride;
    valarray d1;
public:
    gslice() = default;    //<< Explicit default constructor
    ~gslice() = default;
    gslice(const gslice&) = default;
    gslice(gslice&&) = default;
    gslice& operator=(const gslice&) = default;
    gslice& operator=(gslice&&) = default;
    // ...
};

This fragment of the implementation of std::gslice (§40.5.6) is equivalent to:

class gslice {
    valarray siz e;
    valarray stride;
    valarray d1;
public:
    // ...
};