Pythonic way to split a list after elements for which a given predicate is true [duplicate]

Answer 1

The easiest way is probably:

out = [[]]
for element in lst:
    out[-1].append(element)
    if predicate(element):
        out.append([])

Note that this would leave an empty list at the end of out, if predicate(element): for the last element. You can remove this by adding:

out = [l for l in out if l]