C++: Calling a constructor to a temporary object

Question

Suppose I have the following:

int main() {
    SomeClass();
    return 0;
}

Without optimization, the SomeClass() constructor will be calle

Answer 1

I'm sure is 'SomeClass::SomeClass()' is not implemented as 'inline', the compiler has no way of knowing that the constructor/destructor has no side effects, and it will call the constructor/destructor always.