Converting list to dataframe in R

Question

So I have a list, say:

L1 <- list(1:10, 5:14, 10:19)

Now I am trying to get the output of the list as dataframe such that my output look

Answer 1

You can unlist and use matrix, then converting to data.frame. It seems to be faster for this case.

as.data.frame(matrix(unlist(L1),nrow=length(L1),byrow=TRUE)

microbenchmark::microbenchmark(
a= map_dfr(L1, ~as.data.frame(t(.x))),
b= do.call(rbind, lapply(L1, function(x) as.data.frame(t(x)))),
c= as.data.frame(t(as.data.frame(L1))),
d= data.table::transpose(as.data.frame(L1)),
e= as.data.frame(matrix(unlist(L1),nrow=length(L1),byrow=TRUE)),
times = 100,unit = "relative")

# Unit: relative
# expr       min        lq      mean    median        uq       max neval
# a  9.146545  8.548656  8.859087  8.859051  9.449237  7.265274   100
# b 13.879833 11.523000 11.433790 10.924726 10.797251 24.012107   100
# c 12.719835 10.635809 10.442108 10.229913 10.259789  7.020377   100
# d 10.439881  9.143530  9.205734  8.859026  9.176125  6.624454   100
# e  1.000000  1.000000  1.000000  1.000000  1.000000  1.000000   100