Is there a way to call a function expecting a pointer without creating variable?

Question

I have this function call:

uint32_t func(uint32_t* a, uint32_t b)

I want to call it with an integer literal like this:

func         


        

Answer 1

I am assuming you want to pass a pointer to an integer 0, and not the 0 (NULL) pointer.

If you don't mind allocating dynamic memory you can do this:

func(new uint32_t(0), b);

However, then you'd have to make sure to deallocate the memory inside the function.

Alternatively, you can use an R-value references (c++11). Then you can use the address of the reference as the pointer inside your function.

R-value reference syntax:

uint32_t func(uint32_t &&a, uint32_t b);