How to pass command line arguments with spaces through a variable in bash

Question

What I\'m trying to achieve is to read command line arguments from a file and invoke a command using them. So essentially I need to pass the arguments through a bash variabl

Answer 1

Use command substitution, to expand the file contents to the command,

/some/command "$(

As an example,

cat file
"aaa bbb" "xxx yyy"

using printf on it INCORRECTLY with cat will produce

printf "%s\n" $(cat file)
"aaa
bbb"
"xxx
yyy"

With proper quoting present, arguments are sent as such without getting split.

printf "%s\n" "$(