function making

Question

Hi I am new to functional programming. What i did is

>>> g=lambda x:x*2
>>> f=g
>>> g=lambda x:f(f(x))
>>> g(9)
36
         


        

Answer 1

This

g=lambda x:x*2
f=g
g=lambda x:f(x)

is equivalent to:

f=lambda x:x*2
g=lambda x:f(x)

When you call g, you get whatever f happens to be defined in the global (or enclosing) scope.

what you're expecting is something like:

f=lambda x:x*2
g=lambda x, f=f:f(x)

That captures the value of f in the outer scope at the time the lambda expression is evaluated.