I need to intake a number like: 200939915
After doing this, which I know how, I need to remove the first number so it becomes: 00939915
What is the best way
An alternative method, although I like Matt Kane's best:
unsigned long n = 42424242; n = n % (unsigned long)pow(10.0, (double)floor(log10(n))); // n = 2424242;