Function names defined as parameters to a function call aren't hoisted. Why not?

Question

Consider the following code.

Notice that a

Answer 1

function b() doesn't exist until the call a(function b() {}); is executed.

JS doesn't search the code for functions, that way. Also, function b() {} isn't a function declaration, you're merely passing it as a parameter. The only way to access that function would be within function a():

function a() {console.log(arguments[0])}
a(function b() {});
//function b() {}

However, this does not mean that you can actually call b() inside a(), since b() is defined in the scope of a's function call, not in the function itself. Basically, the name b is useless.