Overloading function using varargs

Question

This will not compile:

public class Methods
{

    public static void method(Integer... i)
    {
        System.out.print(\"A\");
    }

    public static vo         


        

Answer 1

Multiple arguments must be passed in an array, but the varargs hides the process. In the above varargs method, parameter acts as an int array with a reference name. So if you change it to:

    public static void main(String args[])
    {
        int[] s = {7};
        method(s);
    }

first class will compile and work properly.