Assignment of address to integer variable

Question

How come you can assign an address to an integer variable like this,the complier will not give an error. i always though you can only assign integer values to a integer vari

Answer 1

0x28ff1c is not an address itself - it's just a hexadecimal number.

The following are equivalent:

int a =   2686748;  //decimal number
int a =  0x28ff1c;  //hexadecimal number
int a = 012177434;  //octal number

An address is represented by a pointer - if it's just that, an address, you can use a void*:

void* p = (void*)0x28ff1c;

In which case

int a = p;

wouldn't compile. p is an address, the number itself isn't.