How to write a template function that takes an array and an int specifying array size

Question

For a university exercise, I have been asked to write a template function \"print();\", which takes two arguments, 1: an array of a generic type, and 2: an int specifying t

Answer 1

If you want to pass the array by reference, you could

template 
void print(const T(&array)[SIZE])
{
    for (size_t i = 0; i < SIZE; i++)
        std::cout << array[i] << " ";
}

and then, e.g.

int x[] = {1, 2, 3};
print(x);

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Otherwise, you can pass it by pointer, note that the array will decay to pointer, and you have to guarantee the correctness of SIZE being passed.

template 
void print(const T array[], size_t SIZE)
{
    for(size_t i = 0; i < SIZE; i++)
        std::cout << array[i] << " ";
}

and then, e.g.

int x[] = {1, 2, 3};
print(x, sizeof(x) / sizeof(int));

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