How to get all indexes of a pattern in a string?

Question

I want something like this:

\"abcdab\".search(/a/g) //return [0,4]

Is it possible?

Answer 1

A non-regex variety:

var str = "abcdabcdabcd",
    char = 'a',
    curr = 0,
    positions = [];

while (str.length > curr) {
    if (str[curr] == char) {
        positions.push(curr);
    }
    curr++;
}

console.log(positions);

http://jsfiddle.net/userdude/HUm8d/