Extracting a part of String using grep/sed

Question

I have a file in linux with similar entries as below

dn: CN=HP_NetworkSupport,OU=groups,DC=HDFCSLDM,DC=COM
dn: CN=Review users,OU=groups,DC=HDFCSLDM,DC=COM
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Answer 1

Using awk

awk -F"=|," '{print $2}' file
HP_NetworkSupport
Review users

or

awk -F[=,] '{print $2}' file
HP_NetworkSupport
Review users

Set the delimiter to , or =, then print second field.

---

To handel field with comma within, you should use a parser for LDAP, but this should work.

echo file
dn: CN=HP_NetworkSupport,OU=groups,DC=HDFCSLDM,DC=COM
dn: CN="Review, users",OU=groups,DC=HDFCSLDM,DC=COM

awk -F"CN=|,OU" '{print $2}' file
HP_NetworkSupport
Review, users