Why does GCC allow use of round() in C++ even with the ansi and pedantic flags?

Question

Is there a good reason why this program compiles under GCC even with the -ansi and -pedantic flags?

#include 

int mai         


        

Answer 1

I might be off base here but doesn't gcc's -ansi flag apply to the code constructs (ie, disable GCC language extensions) rather than switching all libraries into strict ANSI compliant mode as well?