Why does new Number(2) != new String(“2”) in JavaScript

Question

The following evaluate to true:

new Number(2) == 2
new String(\"2\") == \"2\"

Obviously, but so do the following:

Answer 1

Just try:

new Number(2) == new Number(2)

that returns

false

and you will have the answer: there are 2 different objects that have 2 different references.