Lambda inside lambda

Question

Just for curiosity. Discovered Lambdas a few days ago. I was jus wondering if something like that can be done:

(Tried on the interpret but none of my tries seemed to

Answer 1

You aren't actually calling the inner lambda:

p = lambda x: (lambda x: x%2)(x)/2

Note in Python 2 this example will always return 0 since the remainder from dividing by 2 will be either 0 or 1 and integer-dividing that result by 2 will result in a truncated 0.