Generic way to create nested dictionary from flat list in python

Question

I am looking for the simplest generic way to convert this python list:

x = [
        {\"foo\":\"A\", \"bar\":\"R\", \"baz\":\"X\"},
                 


        

Answer 1

#!/usr/bin/env python3
from itertools import groupby
from pprint import pprint

x = [
        {"foo":"A", "bar":"R", "baz":"X"},
        {"foo":"A", "bar":"R", "baz":"Y"},
        {"foo":"B", "bar":"S", "baz":"X"},
        {"foo":"A", "bar":"S", "baz":"Y"},
        {"foo":"C", "bar":"R", "baz":"Y"},
    ]


def fun(x, l):
    ks = ['foo', 'bar', 'baz']
    kn = ks[l]
    kk = lambda i:i[kn]
    for k,g in groupby(sorted(x, key=kk), key=kk):
        kg = [dict((k,v) for k,v in i.items() if k!=kn) for i in g]
        d = {}
        d[kn] = k
        if l

---

[{'bars': [{'bar': 'R', 'bazs': [{'baz': 'X'}, {'baz': 'Y'}]},
           {'bar': 'S', 'bazs': [{'baz': 'Y'}]}],
  'foo': 'A'},
 {'bars': [{'bar': 'S', 'bazs': [{'baz': 'X'}]}], 'foo': 'B'},
 {'bars': [{'bar': 'R', 'bazs': [{'baz': 'Y'}]}], 'foo': 'C'}]

---

note: dict is unordered! but it's the same as yours.